If it's not what You are looking for type in the equation solver your own equation and let us solve it.
25^2x+1=125^-x+2
We move all terms to the left:
25^2x+1-(125^-x+2)=0
We get rid of parentheses
25^2x+x-2+1-125^=0
We add all the numbers together, and all the variables
x+25^2x=0
| x2=9196 | | 3t-t+4t=18 | | 11/6=x+7/9= | | (7+b)•4=48 | | -6x-6(-2x-17)=54 | | c-c+4c-2c=2 | | 5+7a=35 | | 286=54-x | | 1.37x=4.11 | | 4/5x—6=-3(4x+5) | | 5y+y=12y= | | 3999a+45=4999a+40 | | 7a-a-5a+3=14 | | 30-y=275 | | 2q+2q-4=20 | | 5j-4j+6j+1=8 | | 7(4x1-1)=49 | | 2/3(x+4)=1/2(4x+5) | | 5+7a=37 | | 7n-4n+3=15 | | 4n-4n+4n=12 | | 30+1/4=1/2x | | -2x-6(-x+21)=-154 | | -2(x+4)+5=8(x+5)+1 | | 4a+a-4a=13 | | 5m+3m-8m+m=7 | | 2.4+a=6.9 | | 13q-8q+2q-6q=17 | | (3x-6)/(x+5)+1=105/(x(x+5))-20/x | | m-25=13 | | -2x-90+8x-3=180 | | 50w=200 |